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Jmc_uk
06-14-2000, 07:51 AM
Yes call me dumb but i actually want to know whats this all about!

If im wrong tell me PLEASE

FSB = Front side bus?
(Speed of the motherboard bus speed)
eg 66, 75, 83, 100 ......

Multiplier = (multiplier of FSB)
eg 3, 3.5, 4, 4.5........

Clock speed = CPU speed
(FSB x Multiplier)
eg 500mhz, 600mhz......

Therefore

If i have a 500 celeron i set settings at:

5(multiplier) x 100(fsb) ?

BUT!

....celerons are 66mhz (fsb) arent they?

BUT!

....Mine is locked at 7.5

Am i wrong?

I just need some basic facts http://sysopt.earthweb.com/forum/smile.gif

JonmaTifa
06-14-2000, 09:24 AM
Yeah, celeron 500s are 7.5 x 66

On my particular mother board, I used the 5x jumper thinking it wouldn't work at all, but apparently it assumed to be 7.5. Using Sandra, it tells me that my bus speed is 66, and my multiplier is 7.5. It says 500mhz celeron at start up, and the benchmarks are accurate for a celeron 500. My guess is that the jumper lock on the celeron chip did an override to my jumpers on the motherboard.....

RobRich
06-14-2000, 09:33 AM
You are correct on the FSB and multipliers. You can dtermine locked multipliers by using the cpu rating cpu with it's defualt FSB:

-Celeron 500 is 66mhz FSB cpu
-That means that it must use a 7.5x multiplier

The multiplier is set within the cpu core on current Intel cpu's, and can not be modified by convential means. The only way currently override one is to obatin an engineering sample, and even some of them require a special program to rewrite the cpu register that stores the multiplier. This bascially means use must o/c Intel cpu's by changing the FSB.

Robert Richmond