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Apostle 83
12-11-1999, 03:44 PM
I am lazy and do not want to take time and figure out how to do this.
Based on the facts that ip no's have four series of numbers, each 256 or under, how many different combos of number can there be, ie 1.1.1.1, 1.255.167.254, etc.
pickel
12-11-1999, 04:01 PM
IP squared x Pi divided by the square root of RAM plus speed of O'clocked chip minus download rate equals......
I use this formula, but it's only good til
Y2K.
Theoretically Speaking...of course http://www.sysopt.com/forum/biggrin.gif
[This message has been edited by pickel (edited 12-11-1999).]
Dominus
12-11-1999, 04:07 PM
Exaclty 4228250625 possible IPs.
Easy.
256 x 256 x 256 x 256
=4,294,967,296
Enough for the moment, but...
There are new protocols in IP designations that are in the pipeline and will address the problem I believe you are referring to...
Naturally, the powers that be want everyone on the planet to have their own distinctive IP address.
U-96
[edit haha Dominus posted as I was writing mine http://www.sysopt.com/forum/wink.gif The disrepancy is because I included zeroes. Of course I could be completely wrong because I'm necking Jameson's and it's Saturday night, so slap me down if that's the case http://www.sysopt.com/forum/smile.gif)
[This message has been edited by U-96 (edited 12-11-1999).]
Pat Kennedy
12-11-1999, 07:28 PM
U got it U-96.
Pat
Dominus
12-11-1999, 08:56 PM
U-96, I'm pretty sure it's
255*256*256*254, as you can't have IPs starting or ending in 0, or 255 due to reservations for subnetting, and diagnostics.
But then again I haven't invested the time to check the math, because I'm kinda lazy. http://www.sysopt.com/forum/smile.gif
Apostle 83
12-11-1999, 09:59 PM
Her har.. garsh I feel dumb. I dunno... the guy at the local comp store and I were talking about it (he was talking) and he made it seem REALLY complex. I just let fear a getta hold of me!
Dominus you are quite correct, I was aiming for the maximum theoretical, not the maximum valid. We're both right in that case! http://www.sysopt.com/forum/smile.gif
U-96
smunzli
12-12-1999, 02:32 PM
addresses that begin with 1 through 126 would have 126 available networks and 16,777,214 available hosts per network.
addresses that begin with 128 through 191 would have 16,384 available networks and 65,534 available hosts per network.
addresses that begin with 192 through 223 would have 2,097,151 available networks and 254 availble hosts per network.
the address 127 is reserved on the local computer for loopback testing and interprocess communication, and therefore is not a vaild network address. addresses 224 and high are reserved for special protocols, and can't be used as host address. host addresses 0 and 255 are used as broadcast addresses and should not be assigned to computers.
so as you can see it would be a whole lot more than 4,294,967,296
enough said
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