Windows Setup & MS-RAMDRIVE

[Woodcycl]

I am donating an old P223 PC to a needy organization. However, after fdisking and then attempting to install Win98 (1st edition) on the 1GB hard drive, .... and typing setup <enter>, and Enter to continue, I receive the message: "Windows Setup requires 7340032 bytes available on C: d"

There is a d: drive -- not sure what it is though. There was only ONE dos parition (or any other partition) found when running fdisk. But, there is a 2MB d: drive that is labed MS-RAMDRIVE.

It appears that when Win98 attempts to run setup -- it looks to the d: drive and since it is less than 7.34MB, gives me an error.

Any help is greatly appreciated.

Thanks.

[BipolarBill]

Apparently, Setup is not seeing your hard drive. The Ramdrive is created by the floppy setup and disappears when you restart. You must specify C:\Windows as the install directory. Id Setup is assigning C: to your CDROM, that's a problem. If you have copied the setup files to a 1GB HDD, you don't have enough room left to install Windows.

[Woodcycl]

After booting from the bootdisk, it shows E as the CDROM drive -- I can do a dir and see the CD ROM contents. However, one note that may be important is that I am unable to perform a scandisk on the C drive - it just says "unable to scan" or something like that.

How can I specify c:\windows as the install directory? Also, doesn't the Win98 CD need to reformat the drive before actually creating the c:\windows directory? I've become so used to working with WinXP ... that it seems I'm a little foggy with working on 98.

I haven't copied any files to the hdd.

:confused:

[BipolarBill]

Is the drive raw? Has it been FDISKed and formatted?

[Woodcycl]

No - only fdisk's. I have always allowed the Windows Setup to re-format the drive. Thoughts?

[BipolarBill]

You can only format a drive by booting from a full-install version of Windows. Otherwise, you have to format before beginning.