Computer Science Question

[Pollux]

K, i've got a test tomorrow and i'm having trouble understanding how memory is addressed. Here's a previous test question that I dont' have the answer for, nor do I know how to come about that answer. The test's in about .... emmm..... 10 hours so any help would be great. http://sysopt.earthweb.com/forum/smile.gif
-Pollux

[daveleau]

What's the question?
Dave

[zygmunt]

Try: http://www.cag.lcs.mit.edu/pub/6.004/Lectures/lect19/

[Mykex]

I usually just say 'hello memory. http://sysopt.earthweb.com/forum/wink.gif sorry couldnt resist and dont know. http://sysopt.earthweb.com/forum/frown.gif

[Pollux]

wow... haha, that's how stressed i've been lately. i forgot to put the question :P It is, if anybody can answer it in 20 minutes:

A computer has 2 bytes in each memory location and a total of 8 address lines.
-What is the total number of addressable locations? ___
-What is the overall size of the memory (in bytes)? ___

thanks again
-Pollux

[mike511]

I could be wrong, but i think the answers to your two questions are:

1) 8bits * 2bytes = 16bits * 8address lines = 128 addressable locations

2)size = 2bytes * 8 address lines = 16 bytes.

as i said i'm not 100% sure, but i think thats right. Hope it helps.

[zskillz]

yo pollux!

I usually take the same approach that mykex takes, but I try to say it with a somewhat stern tone!

peace dog!
-Z

[Banti]

been a while since I did these computations...

lets see 8 lines means 2^8 locations... is 256 locations

at 2 bytes each 512 bytes memory

[This message has been edited by Banti (edited 12-12-2000).]